Cole, Daniel and Fred had a total of 59 stamps. The ratio of the number of stamps that Daniel had to the number of stamps that Fred had was 4 : 3. After Cole and Daniel each gave away half of their stamps, the 3 children had 37 stamps left. How many stamps did Daniel and Fred have in the end?
| |
Cole |
Daniel |
Fred |
Total |
| Before |
2 p |
4 u |
3 u |
59 |
| Change |
- 1 p |
- 2 u |
|
- 22 |
| After |
1 p |
2 u |
3 u |
37 |
Total number of stamps that Cole and Daniel gave away
= 59 - 37
= 22
1 p + 2 u = 22 --- (1)
1 p + 2 u + 3 u = 37
1 p + 5 u = 37 --- (2)
(2) - (1)
(1 p + 5 u) - (1 p + 2 u) = 37 - 22
5 u - 2 u = 15
3 u = 15
1 u = 15 ÷ 3 = 5
Total number of stamps that Daniel and Fred had in the end
= 2 u + 3 u
= 5 u
= 5 x 5
= 25
Answer(s): 25
