Howard, Harry and Ian had a total of 78 stamps. The ratio of the number of stamps that Harry had to the number of stamps that Ian had was 2 : 5. After Howard and Harry each gave away half of their stamps, the 3 children had 64 stamps left. How many stamps did Harry and Ian have at first?
| |
Howard |
Harry |
Ian |
Total |
| Before |
2 p |
2 u |
5 u |
78 |
| Change |
- 1 p |
- 1 u |
|
- 14 |
| After |
1 p |
1 u |
5 u |
64 |
Total number of stamps that Howard and Harry gave away
= 78 - 64
= 14
1 p + 1 u = 14 --- (1)
1 p + 1 u + 5 u = 64
1 p + 6 u = 64 --- (2)
(2) - (1)
(1 p + 6 u) - (1 p + 1 u) = 64 - 14
6 u - 1 u = 50
5 u = 50
1 u = 50 ÷ 5 = 10
Total number of stamps that Harry and Ian had at first
= 2 u + 5 u
= 7 u
= 7 x 10
= 70
Answer(s): 70
