Tommy, Paul and Cody had a total of 82 stamps. The ratio of the number of stamps that Paul had to the number of stamps that Cody had was 2 : 5. After Tommy and Paul each gave away half of their stamps, the 3 children had 66 stamps left. How many stamps did Paul and Cody have in the end?
| |
Tommy |
Paul |
Cody |
Total |
| Before |
2 p |
2 u |
5 u |
82 |
| Change |
- 1 p |
- 1 u |
|
- 16 |
| After |
1 p |
1 u |
5 u |
66 |
Total number of stamps that Tommy and Paul gave away
= 82 - 66
= 16
1 p + 1 u = 16 --- (1)
1 p + 1 u + 5 u = 66
1 p + 6 u = 66 --- (2)
(2) - (1)
(1 p + 6 u) - (1 p + 1 u) = 66 - 16
6 u - 1 u = 50
5 u = 50
1 u = 50 ÷ 5 = 10
Total number of stamps that Paul and Cody had in the end
= 1 u + 5 u
= 6 u
= 6 x 10
= 60
Answer(s): 60
