Xavier, Will and Cole had a total of 113 stamps. The ratio of the number of stamps that Will had to the number of stamps that Cole had was 6 : 5. After Xavier and Will each gave away half of their stamps, the 3 children had 79 stamps left. How many stamps did Will and Cole have at first?
| |
Xavier |
Will |
Cole |
Total |
| Before |
2 p |
6 u |
5 u |
113 |
| Change |
- 1 p |
- 3 u |
|
- 34 |
| After |
1 p |
3 u |
5 u |
79 |
Total number of stamps that Xavier and Will gave away
= 113 - 79
= 34
1 p + 3 u = 34 --- (1)
1 p + 3 u + 5 u = 79
1 p + 8 u = 79 --- (2)
(2) - (1)
(1 p + 8 u) - (1 p + 3 u) = 79 - 34
8 u - 3 u = 45
5 u = 45
1 u = 45 ÷ 5 = 9
Total number of stamps that Will and Cole had at first
= 6 u + 5 u
= 11 u
= 11 x 9
= 99
Answer(s): 99
