Tim, Xavier and Justin had a total of 56 stamps. The ratio of the number of stamps that Xavier had to the number of stamps that Justin had was 6 : 7. After Tim and Xavier each gave away half of their stamps, the 3 children had 42 stamps left. How many stamps did Xavier and Justin have in the end?
| |
Tim |
Xavier |
Justin |
Total |
| Before |
2 p |
6 u |
7 u |
56 |
| Change |
- 1 p |
- 3 u |
|
- 14 |
| After |
1 p |
3 u |
7 u |
42 |
Total number of stamps that Tim and Xavier gave away
= 56 - 42
= 14
1 p + 3 u = 14 --- (1)
1 p + 3 u + 7 u = 42
1 p + 10 u = 42 --- (2)
(2) - (1)
(1 p + 10 u) - (1 p + 3 u) = 42 - 14
10 u - 3 u = 28
7 u = 28
1 u = 28 ÷ 7 = 4
Total number of stamps that Xavier and Justin had in the end
= 3 u + 7 u
= 10 u
= 10 x 4
= 40
Answer(s): 40
