Ivan, Neave and Ahmad had a total of 89 stamps. The ratio of the number of stamps that Neave had to the number of stamps that Ahmad had was 6 : 7. After Ivan and Neave each gave away half of their stamps, the 3 children had 62 stamps left. How many stamps did Neave and Ahmad have at first?
| |
Ivan |
Neave |
Ahmad |
Total |
| Before |
2 p |
6 u |
7 u |
89 |
| Change |
- 1 p |
- 3 u |
|
- 27 |
| After |
1 p |
3 u |
7 u |
62 |
Total number of stamps that Ivan and Neave gave away
= 89 - 62
= 27
1 p + 3 u = 27 --- (1)
1 p + 3 u + 7 u = 62
1 p + 10 u = 62 --- (2)
(2) - (1)
(1 p + 10 u) - (1 p + 3 u) = 62 - 27
10 u - 3 u = 35
7 u = 35
1 u = 35 ÷ 7 = 5
Total number of stamps that Neave and Ahmad had at first
= 6 u + 7 u
= 13 u
= 13 x 5
= 65
Answer(s): 65
