Rael, Wesley and George had a total of 24 coins. The ratio of the number of coins that Wesley had to the number of coins that George had was 4 : 3. After Rael and Wesley each gave away half of their coins, the 3 children had 15 coins left. How many coins did Wesley and George have at first?
| |
Rael |
Wesley |
George |
Total |
| Before |
2 p |
4 u |
3 u |
24 |
| Change |
- 1 p |
- 2 u |
|
- 9 |
| After |
1 p |
2 u |
3 u |
15 |
Total number of coins that Rael and Wesley gave away
= 24 - 15
= 9
1 p + 2 u = 9 --- (1)
1 p + 2 u + 3 u = 15
1 p + 5 u = 15 --- (2)
(2) - (1)
(1 p + 5 u) - (1 p + 2 u) = 15 - 9
5 u - 2 u = 6
3 u = 6
1 u = 6 ÷ 3 = 2
Total number of coins that Wesley and George had at first
= 4 u + 3 u
= 7 u
= 7 x 2
= 14
Answer(s): 14
