Sam, Henry and Flynn had a total of 40 coins. The ratio of the number of coins that Henry had to the number of coins that Flynn had was 2 : 7. After Sam and Henry each gave away half of their coins, the 3 children had 27 coins left. How many coins did Henry and Flynn have at first?
| |
Sam |
Henry |
Flynn |
Total |
| Before |
2 p |
2 u |
7 u |
40 |
| Change |
- 1 p |
- 1 u |
|
- 13 |
| After |
1 p |
1 u |
7 u |
27 |
Total number of coins that Sam and Henry gave away
= 40 - 27
= 13
1 p + 1 u = 13 --- (1)
1 p + 1 u + 7 u = 27
1 p + 8 u = 27 --- (2)
(2) - (1)
(1 p + 8 u) - (1 p + 1 u) = 27 - 13
8 u - 1 u = 14
7 u = 14
1 u = 14 ÷ 7 = 2
Total number of coins that Henry and Flynn had at first
= 2 u + 7 u
= 9 u
= 9 x 2
= 18
Answer(s): 18
