Xylia and Irene had equal amount of money. Each day, Xylia spent $9 and Irene spent $19. When Xylia had $120 left, Irene had
23 as much money left as Xylia. How much money did the two girls have at first?
| |
Xylia |
Irene |
| Before |
9 u + 120 |
19 u + 80 |
| Change |
- 9 u |
- 19 u |
| After |
$120 |
$80 |
Amount that Irene had left
=
23 x 120
= $80
The amount that Xylia and Irene had at first is the same.
19 u + 80 = 9 u + 120
19 u - 9 u = 120 - 80
10 u = 40
1 u = 40 ÷ 10 = 4
Amount that Xylia had at first
= 9 u + 120
= 9 x 4 + 120
= 36 + 120
= $156
Total amount that both girls had at first
= 2 x 156
= $312
Answer(s): $312
