Penelope and Min had equal amount of money. Each day, Penelope spent $8 and Min spent $16. When Penelope had $80 left, Min had
710 as much money left as Penelope. How much money did the two girls have at first?
| |
Penelope |
Min |
| Before |
8 u + 80 |
16 u + 56 |
| Change |
- 8 u |
- 16 u |
| After |
$80 |
$56 |
Amount that Min had left
=
710 x 80
= $56
The amount that Penelope and Min had at first is the same.
16 u + 56 = 8 u + 80
16 u - 8 u = 80 - 56
8 u = 24
1 u = 24 ÷ 8 = 3
Amount that Penelope had at first
= 8 u + 80
= 8 x 3 + 80
= 24 + 80
= $104
Total amount that both girls had at first
= 2 x 104
= $208
Answer(s): $208
