Shiyun and Marion had equal amount of money. Each day, Shiyun spent $3 and Marion spent $13. When Shiyun had $110 left, Marion had
211 as much money left as Shiyun. How much money did the two girls have at first?
| |
Shiyun |
Marion |
| Before |
3 u + 110 |
13 u + 20 |
| Change |
- 3 u |
- 13 u |
| After |
$110 |
$20 |
Amount that Marion had left
=
211 x 110
= $20
The amount that Shiyun and Marion had at first is the same.
13 u + 20 = 3 u + 110
13 u - 3 u = 110 - 20
10 u = 90
1 u = 90 ÷ 10 = 9
Amount that Shiyun had at first
= 3 u + 110
= 3 x 9 + 110
= 27 + 110
= $137
Total amount that both girls had at first
= 2 x 137
= $274
Answer(s): $274
