Roshel and Kimberly had equal amount of money. Each day, Roshel spent $20 and Kimberly spent $29. When Roshel had $108 left, Kimberly had
512 as much money left as Roshel. How much money did the two girls have at first?
| |
Roshel |
Kimberly |
| Before |
20 u + 108 |
29 u + 45 |
| Change |
- 20 u |
- 29 u |
| After |
$108 |
$45 |
Amount that Kimberly had left
=
512 x 108
= $45
The amount that Roshel and Kimberly had at first is the same.
29 u + 45 = 20 u + 108
29 u - 20 u = 108 - 45
9 u = 63
1 u = 63 ÷ 9 = 7
Amount that Roshel had at first
= 20 u + 108
= 20 x 7 + 108
= 140 + 108
= $248
Total amount that both girls had at first
= 2 x 248
= $496
Answer(s): $496
