Linda and Opal had equal amount of money. Each day, Linda spent $19 and Opal spent $27. When Linda had $88 left, Opal had
711 as much money left as Linda. How much money did the two girls have at first?
| |
Linda |
Opal |
| Before |
19 u + 88 |
27 u + 56 |
| Change |
- 19 u |
- 27 u |
| After |
$88 |
$56 |
Amount that Opal had left
=
711 x 88
= $56
The amount that Linda and Opal had at first is the same.
27 u + 56 = 19 u + 88
27 u - 19 u = 88 - 56
8 u = 32
1 u = 32 ÷ 8 = 4
Amount that Linda had at first
= 19 u + 88
= 19 x 4 + 88
= 76 + 88
= $164
Total amount that both girls had at first
= 2 x 164
= $328
Answer(s): $328
