Marion and Kimberly had equal amount of money. Each day, Marion spent $18 and Kimberly spent $23. When Marion had $90 left, Kimberly had
13 as much money left as Marion. How much money did the two girls have at first?
| |
Marion |
Kimberly |
| Before |
18 u + 90 |
23 u + 30 |
| Change |
- 18 u |
- 23 u |
| After |
$90 |
$30 |
Amount that Kimberly had left
=
13 x 90
= $30
The amount that Marion and Kimberly had at first is the same.
23 u + 30 = 18 u + 90
23 u - 18 u = 90 - 30
5 u = 60
1 u = 60 ÷ 5 = 12
Amount that Marion had at first
= 18 u + 90
= 18 x 12 + 90
= 216 + 90
= $306
Total amount that both girls had at first
= 2 x 306
= $612
Answer(s): $612
