Penelope and Mary had equal amount of money. Each day, Penelope spent $11 and Mary spent $15. When Penelope had $80 left, Mary had
710 as much money left as Penelope. How much money did the two girls have at first?
| |
Penelope |
Mary |
| Before |
11 u + 80 |
15 u + 56 |
| Change |
- 11 u |
- 15 u |
| After |
$80 |
$56 |
Amount that Mary had left
=
710 x 80
= $56
The amount that Penelope and Mary had at first is the same.
15 u + 56 = 11 u + 80
15 u - 11 u = 80 - 56
4 u = 24
1 u = 24 ÷ 4 = 6
Amount that Penelope had at first
= 11 u + 80
= 11 x 6 + 80
= 66 + 80
= $146
Total amount that both girls had at first
= 2 x 146
= $292
Answer(s): $292
