Gem and Min had equal amount of money. Each day, Gem spent $8 and Min spent $10. When Gem had $88 left, Min had
111 as much money left as Gem. How much money did the two girls have at first?
| |
Gem |
Min |
| Before |
8 u + 88 |
10 u + 8 |
| Change |
- 8 u |
- 10 u |
| After |
$88 |
$8 |
Amount that Min had left
=
111 x 88
= $8
The amount that Gem and Min had at first is the same.
10 u + 8 = 8 u + 88
10 u - 8 u = 88 - 8
2 u = 80
1 u = 80 ÷ 2 = 40
Amount that Gem had at first
= 8 u + 88
= 8 x 40 + 88
= 320 + 88
= $408
Total amount that both girls had at first
= 2 x 408
= $816
Answer(s): $816
