The ratio of Pierre's money to Lee's money is 5 : 11. If Lee has $308, how much must he give to Pierre so both will have the equal amount of money?
| |
Pierre |
Lee |
Total |
| Before |
5 u |
11 u |
16 u |
| Change |
+ 3 u |
- 3 u |
|
| After |
8 u |
8 u |
16 u |
Comparing Pierre and
Lee in the end |
1 |
1 |
|
Amount that Lee has at first = 11 u
11 u = 308
1 u = 308 ÷ 11 = 28
Total amount that Lee and Pierre have
= 5 u + 11 u
= 16 u
Amount that each of them will have in the end
= 16 u ÷ 2
= 8 u
Amount that Lee must give to Pierre
= 8 u - 5 u
= 3 u
= 3 x 28
= $84
Answer(s): $84
