The ratio of Pierre's money to Cody's money is 3 : 7. If Cody has $91, how much must he give to Pierre so both will have the equal amount of money?
| |
Pierre |
Cody |
Total |
| Before |
3 u |
7 u |
10 u |
| Change |
+ 2 u |
- 2 u |
|
| After |
5 u |
5 u |
10 u |
Comparing Pierre and
Cody in the end |
1 |
1 |
|
Amount that Cody has at first = 7 u
7 u = 91
1 u = 91 ÷ 7 = 13
Total amount that Cody and Pierre have
= 3 u + 7 u
= 10 u
Amount that each of them will have in the end
= 10 u ÷ 2
= 5 u
Amount that Cody must give to Pierre
= 5 u - 3 u
= 2 u
= 2 x 13
= $26
Answer(s): $26
