The ratio of Cody's money to Pierre's money is 7 : 11. If Pierre has $308, how much must he give to Cody so both will have the equal amount of money?
| |
Cody |
Pierre |
Total |
| Before |
7 u |
11 u |
18 u |
| Change |
+ 2 u |
- 2 u |
|
| After |
9 u |
9 u |
18 u |
Comparing Cody and
Pierre in the end |
1 |
1 |
|
Amount that Pierre has at first = 11 u
11 u = 308
1 u = 308 ÷ 11 = 28
Total amount that Pierre and Cody have
= 7 u + 11 u
= 18 u
Amount that each of them will have in the end
= 18 u ÷ 2
= 9 u
Amount that Pierre must give to Cody
= 9 u - 7 u
= 2 u
= 2 x 28
= $56
Answer(s): $56
