At a park, there were
37 as many adults as children at first. After 51 adults left, there were 199 more children than adults remaining at a park. How many adults were at the park at first?
|
Adults |
Children |
Before |
3 u |
7 u |
Change |
- 51 |
|
After |
3 u - 51 |
7 u |
In the end, the number of children was 199 more than the number of adults. If another 199 adults entered the park, the number of children and adults would be the same.
7 u = 3 u - 51 + 199
7 u - 3 u = 199 - 51
4 u = 148
1 u = 148 ÷ 4 = 37
Number of adults at first
= 3 u
= 3 x 37
= 111
Answer: 111