At a stadium, there were
47 as many adults as children at first. After 74 adults left, there were 131 more children than adults remaining at a stadium. How many children were at the stadium?
|
Adults |
Children |
Before |
4 u |
7 u |
Change |
- 74 |
|
After |
4 u - 74 |
7 u |
In the end, the number of children was 131 more than the number of adults. If another 131 adults entered the stadium, the number of children and adults would be the same.
7 u = 4 u - 74 + 131
7 u - 4 u = 131 - 74
3 u = 57
1 u = 57 ÷ 3 = 19
Number of children at first
= 7 u
= 7 x 19
= 133
Answer: 133