At a park, there were
47 as many adults as children at first. After 76 adults left, there were 124 more children than adults remaining at a park. How many children were at the park?
| |
Adults |
Children |
| Before |
4 u |
7 u |
| Change |
- 76 |
|
| After |
4 u - 76 |
7 u |
In the end, the number of children was 124 more than the number of adults. If another 124 adults entered the park, the number of children and adults would be the same.
7 u = 4 u - 76 + 124
7 u - 4 u = 124 - 76
3 u = 48
1 u = 48 ÷ 3 = 16
Number of children at first
= 7 u
= 7 x 16
= 112
Answer: 112
