At a concert hall, there were
38 as many adults as children at first. After 56 adults left, there were 121 more children than adults remaining at a concert hall. How many children were at the concert hall?
| |
Adults |
Children |
| Before |
3 u |
8 u |
| Change |
- 56 |
|
| After |
3 u - 56 |
8 u |
In the end, the number of children was 121 more than the number of adults. If another 121 adults entered the concert hall, the number of children and adults would be the same.
8 u = 3 u - 56 + 121
8 u - 3 u = 121 - 56
5 u = 65
1 u = 65 ÷ 5 = 13
Number of children at first
= 8 u
= 8 x 13
= 104
Answer: 104
