Xavier had
49 as many coins as Esther. After Xavier gave away 69 coins, he had 79 less coins than Esther. How many coins did Esther have?
|
Xavier |
Esther |
Before |
4 u |
9 u |
Change |
- 69 |
|
After |
4 u - 69 |
9 u |
Esther had 79 more coins than Xavier in the end. So, if Xavier had another 79 coins, he would have the same number of coins as Esther.
9 u = 4 u - 69 + 79
9 u - 4 u = 79 - 69
5 u = 10
1 u = 10 ÷ 5 = 2
Number of coins that Esther had at first
= 9 u
= 9 x 2
= 18
Answer: 18