Xavier had
49 as many buttons as Dana. After Xavier bought another 26 buttons, he had 14 less buttons than Dana. How many buttons did Xavier have at first?
|
Xavier |
Dana |
Before |
4 u |
9 u |
Change |
+ 26 |
|
After |
4 u + 26 |
9 u |
Dana had 14 more buttons than Xavier in the end. So, if Xavier had another 14 buttons, he would have the same number of buttons as Dana.
9 u = 4 u + 26 + 14
9 u - 4 u = 26 + 14
5 u = 40
1 u = 40 ÷ 5 = 8
Number of buttons that Xavier had at first
= 4 u
= 4 x 8
= 32
Answer: 32