Michael had
310 as many coins as Kylie. After Michael bought another 62 coins, he had 15 less coins than Kylie. How many coins did Michael have at first?
|
Michael |
Kylie |
Before |
3 u |
10 u |
Change |
+ 62 |
|
After |
3 u + 62 |
10 u |
Kylie had 15 more coins than Michael in the end. So, if Michael had another 15 coins, he would have the same number of coins as Kylie.
10 u = 3 u + 62 + 15
10 u - 3 u = 62 + 15
7 u = 77
1 u = 77 ÷ 7 = 11
Number of coins that Michael had at first
= 3 u
= 3 x 11
= 33
Answer: 33