Xavier had
35 as many coins as Kathy. After Xavier gave away 76 coins, he had 98 less coins than Kathy. How many coins did Kathy have?
|
Xavier |
Kathy |
Before |
3 u |
5 u |
Change |
- 76 |
|
After |
3 u - 76 |
5 u |
Kathy had 98 more coins than Xavier in the end. So, if Xavier had another 98 coins, he would have the same number of coins as Kathy.
5 u = 3 u - 76 + 98
5 u - 3 u = 98 - 76
2 u = 22
1 u = 22 ÷ 2 = 11
Number of coins that Kathy had at first
= 5 u
= 5 x 11
= 55
Answer: 55