David had
58 as many coins as Pamela. After David gave away 64 coins, he had 82 less coins than Pamela. How many coins did Pamela have?
| |
David |
Pamela |
| Before |
5 u |
8 u |
| Change |
- 64 |
|
| After |
5 u - 64 |
8 u |
Pamela had 82 more coins than David in the end. So, if David had another 82 coins, he would have the same number of coins as Pamela.
8 u = 5 u - 64 + 82
8 u - 5 u = 82 - 64
3 u = 18
1 u = 18 ÷ 3 = 6
Number of coins that Pamela had at first
= 8 u
= 8 x 6
= 48
Answer: 48
