Tim had
29 as many coins as Jean. After Tim bought another 117 coins, he had 16 less coins than Jean. How many coins did Tim have at first?
|
Tim |
Jean |
Before |
2 u |
9 u |
Change |
+ 117 |
|
After |
2 u + 117 |
9 u |
Jean had 16 more coins than Tim in the end. So, if Tim had another 16 coins, he would have the same number of coins as Jean.
9 u = 2 u + 117 + 16
9 u - 2 u = 117 + 16
7 u = 133
1 u = 133 ÷ 7 = 19
Number of coins that Tim had at first
= 2 u
= 2 x 19
= 38
Answer: 38