Howard had
710 as many pens as Cindy. After Howard bought another 27 pens, he had 15 less pens than Cindy. How many pens did Howard have at first?
|
Howard |
Cindy |
Before |
7 u |
10 u |
Change |
+ 27 |
|
After |
7 u + 27 |
10 u |
Cindy had 15 more pens than Howard in the end. So, if Howard had another 15 pens, he would have the same number of pens as Cindy.
10 u = 7 u + 27 + 15
10 u - 7 u = 27 + 15
3 u = 42
1 u = 42 ÷ 3 = 14
Number of pens that Howard had at first
= 7 u
= 7 x 14
= 98
Answer: 98