Luis had
49 as many coins as Ivory. After Luis bought another 61 coins, he had 19 less coins than Ivory. How many coins did Luis have at first?
|
Luis |
Ivory |
Before |
4 u |
9 u |
Change |
+ 61 |
|
After |
4 u + 61 |
9 u |
Ivory had 19 more coins than Luis in the end. So, if Luis had another 19 coins, he would have the same number of coins as Ivory.
9 u = 4 u + 61 + 19
9 u - 4 u = 61 + 19
5 u = 80
1 u = 80 ÷ 5 = 16
Number of coins that Luis had at first
= 4 u
= 4 x 16
= 64
Answer: 64