Bryan had
58 as many coins as Xylia. After Bryan gave away 56 coins, he had 98 less coins than Xylia. How many coins did Xylia have?
|
Bryan |
Xylia |
Before |
5 u |
8 u |
Change |
- 56 |
|
After |
5 u - 56 |
8 u |
Xylia had 98 more coins than Bryan in the end. So, if Bryan had another 98 coins, he would have the same number of coins as Xylia.
8 u = 5 u - 56 + 98
8 u - 5 u = 98 - 56
3 u = 42
1 u = 42 ÷ 3 = 14
Number of coins that Xylia had at first
= 8 u
= 8 x 14
= 112
Answer: 112