Lee had
29 as many stamps as Esther. After Lee bought another 46 stamps, he had 10 less stamps than Esther. How many stamps did Lee have at first?
|
Lee |
Esther |
Before |
2 u |
9 u |
Change |
+ 46 |
|
After |
2 u + 46 |
9 u |
Esther had 10 more stamps than Lee in the end. So, if Lee had another 10 stamps, he would have the same number of stamps as Esther.
9 u = 2 u + 46 + 10
9 u - 2 u = 46 + 10
7 u = 56
1 u = 56 ÷ 7 = 8
Number of stamps that Lee had at first
= 2 u
= 2 x 8
= 16
Answer: 16