Ahmad had
58 as many coins as Hazel. After Ahmad gave away 59 coins, he had 74 less coins than Hazel. How many coins did Hazel have?
|
Ahmad |
Hazel |
Before |
5 u |
8 u |
Change |
- 59 |
|
After |
5 u - 59 |
8 u |
Hazel had 74 more coins than Ahmad in the end. So, if Ahmad had another 74 coins, he would have the same number of coins as Hazel.
8 u = 5 u - 59 + 74
8 u - 5 u = 74 - 59
3 u = 15
1 u = 15 ÷ 3 = 5
Number of coins that Hazel had at first
= 8 u
= 8 x 5
= 40
Answer: 40