Xavier had
59 as many coins as Jean. After Xavier gave away 52 coins, he had 60 less coins than Jean. How many coins did Jean have?
|
Xavier |
Jean |
Before |
5 u |
9 u |
Change |
- 52 |
|
After |
5 u - 52 |
9 u |
Jean had 60 more coins than Xavier in the end. So, if Xavier had another 60 coins, he would have the same number of coins as Jean.
9 u = 5 u - 52 + 60
9 u - 5 u = 60 - 52
4 u = 8
1 u = 8 ÷ 4 = 2
Number of coins that Jean had at first
= 9 u
= 9 x 2
= 18
Answer: 18