Ken had
49 as many coins as Elyse. After Ken bought another 58 coins, he had 17 less coins than Elyse. How many coins did Ken have at first?
|
Ken |
Elyse |
Before |
4 u |
9 u |
Change |
+ 58 |
|
After |
4 u + 58 |
9 u |
Elyse had 17 more coins than Ken in the end. So, if Ken had another 17 coins, he would have the same number of coins as Elyse.
9 u = 4 u + 58 + 17
9 u - 4 u = 58 + 17
5 u = 75
1 u = 75 ÷ 5 = 15
Number of coins that Ken had at first
= 4 u
= 4 x 15
= 60
Answer: 60