Tim had
58 as many coins as Dana. After Tim gave away 14 coins, he had 65 less coins than Dana. How many coins did Dana have?
| |
Tim |
Dana |
| Before |
5 u |
8 u |
| Change |
- 14 |
|
| After |
5 u - 14 |
8 u |
Dana had 65 more coins than Tim in the end. So, if Tim had another 65 coins, he would have the same number of coins as Dana.
8 u = 5 u - 14 + 65
8 u - 5 u = 65 - 14
3 u = 51
1 u = 51 ÷ 3 = 17
Number of coins that Dana had at first
= 8 u
= 8 x 17
= 136
Answer: 136
