Paul had
38 as many coins as Irene. After Paul gave away 22 coins, he had 62 less coins than Irene. How many coins did Irene have?
|
Paul |
Irene |
Before |
3 u |
8 u |
Change |
- 22 |
|
After |
3 u - 22 |
8 u |
Irene had 62 more coins than Paul in the end. So, if Paul had another 62 coins, he would have the same number of coins as Irene.
8 u = 3 u - 22 + 62
8 u - 3 u = 62 - 22
5 u = 40
1 u = 40 ÷ 5 = 8
Number of coins that Irene had at first
= 8 u
= 8 x 8
= 64
Answer: 64