Eric had
49 as many stamps as Erika. After Eric bought another 80 stamps, he had 15 less stamps than Erika. How many stamps did Eric have at first?
| |
Eric |
Erika |
| Before |
4 u |
9 u |
| Change |
+ 80 |
|
| After |
4 u + 80 |
9 u |
Erika had 15 more stamps than Eric in the end. So, if Eric had another 15 stamps, he would have the same number of stamps as Erika.
9 u = 4 u + 80 + 15
9 u - 4 u = 80 + 15
5 u = 95
1 u = 95 ÷ 5 = 19
Number of stamps that Eric had at first
= 4 u
= 4 x 19
= 76
Answer: 76
