Xavier had
35 as many coins as Shannon. After Xavier bought another 19 coins, he had 13 less coins than Shannon. How many coins did Xavier have at first?
|
Xavier |
Shannon |
Before |
3 u |
5 u |
Change |
+ 19 |
|
After |
3 u + 19 |
5 u |
Shannon had 13 more coins than Xavier in the end. So, if Xavier had another 13 coins, he would have the same number of coins as Shannon.
5 u = 3 u + 19 + 13
5 u - 3 u = 19 + 13
2 u = 32
1 u = 32 ÷ 2 = 16
Number of coins that Xavier had at first
= 3 u
= 3 x 16
= 48
Answer: 48