Carl had
710 as many coins as Natalie. After Carl gave away 39 coins, he had 72 less coins than Natalie. How many coins did Natalie have?
| |
Carl |
Natalie |
| Before |
7 u |
10 u |
| Change |
- 39 |
|
| After |
7 u - 39 |
10 u |
Natalie had 72 more coins than Carl in the end. So, if Carl had another 72 coins, he would have the same number of coins as Natalie.
10 u = 7 u - 39 + 72
10 u - 7 u = 72 - 39
3 u = 33
1 u = 33 ÷ 3 = 11
Number of coins that Natalie had at first
= 10 u
= 10 x 11
= 110
Answer: 110
