Brandon had
58 as many cards as Tina. After Brandon bought another 35 cards, he had 10 less cards than Tina. How many cards did Brandon have at first?
| |
Brandon |
Tina |
| Before |
5 u |
8 u |
| Change |
+ 35 |
|
| After |
5 u + 35 |
8 u |
Tina had 10 more cards than Brandon in the end. So, if Brandon had another 10 cards, he would have the same number of cards as Tina.
8 u = 5 u + 35 + 10
8 u - 5 u = 35 + 10
3 u = 45
1 u = 45 ÷ 3 = 15
Number of cards that Brandon had at first
= 5 u
= 5 x 15
= 75
Answer: 75
