Dylan had
35 as many coins as Mary. After Dylan gave away 37 coins, he had 51 less coins than Mary. How many coins did Mary have?
| |
Dylan |
Mary |
| Before |
3 u |
5 u |
| Change |
- 37 |
|
| After |
3 u - 37 |
5 u |
Mary had 51 more coins than Dylan in the end. So, if Dylan had another 51 coins, he would have the same number of coins as Mary.
5 u = 3 u - 37 + 51
5 u - 3 u = 51 - 37
2 u = 14
1 u = 14 ÷ 2 = 7
Number of coins that Mary had at first
= 5 u
= 5 x 7
= 35
Answer: 35
