Jeremy had
38 the number of beads that Cole had at first. After Cole gave Jeremy 12 of his beads, Jeremy had
37 the number of beads that Cole had. How many beads did Cole have in the end?
| |
Jeremy |
Cole |
Total |
| Before |
3x10 =
30 u |
8x10 =
80 u |
11x10 =
110 u |
| Change |
+ 3 u |
- 3 u |
|
| After |
3x11 =
33 u |
7x11 =
77 u |
10x11 =
110 u |
The total number of beads that Jeremy and Cole had at first and in the end remains unchanged. Make the total number of beads the same. LCM of 11 and 10 is 110.
Number of beads that Cole gave Jeremy
= 33 u - 30 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of beads that Cole had in the end
= 77 u
= 77 x 4
= 308
Answer(s): 308
