Owen had
25 the number of coins that Ahmad had at first. After Ahmad gave Owen 40 of his coins, Owen had
35 the number of coins that Ahmad had. How many coins did Ahmad have in the end?
|
Owen |
Ahmad |
Total |
Before |
2x8 = 16 u |
5x8 = 40 u |
7x8 = 56 u |
Change |
+ 5 u |
- 5 u |
|
After |
3x7 = 21 u |
5x7 = 35 u |
8x7 = 56 u |
The total number of coins that Owen and Ahmad had at first and in the end remains unchanged. Make the total number of coins the same. LCM of 7 and 8 is 56.
Number of coins that Ahmad gave Owen
= 21 u - 16 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of coins that Ahmad had in the end
= 35 u
= 35 x 8
= 280
Answer(s): 280