Ken had
35 the number of erasers that Sean had at first. After Sean gave Ken 18 of his erasers, Ken had
34 the number of erasers that Sean had. How many erasers did Ken have at first?
|
Ken |
Sean |
Total |
Before |
3x7 = 21 u |
5x7 = 35 u |
8x7 = 56 u |
Change |
+ 3 u |
- 3 u |
|
After |
3x8 = 24 u |
4x8 = 32 u |
7x8 = 56 u |
The total number of erasers that Ken and Sean had at first and in the end remains unchanged. Make the total number of erasers the same. LCM of 8 and 7 is 56.
Number of erasers that Sean gave Ken
= 24 u - 21 u
= 3 u
3 u = 18
1 u = 18 ÷ 3 = 6
Number of erasers that Ken had at first
= 21 u
= 21 x 6
= 126
Answer(s): 126