George had
25 the number of beads that Jeremy had at first. After Jeremy gave George 50 of his beads, George had
35 the number of beads that Jeremy had. How many beads did George have at first?
| |
George |
Jeremy |
Total |
| Before |
2x8 =
16 u |
5x8 =
40 u |
7x8 =
56 u |
| Change |
+ 5 u |
- 5 u |
|
| After |
3x7 =
21 u |
5x7 =
35 u |
8x7 =
56 u |
The total number of beads that George and Jeremy had at first and in the end remains unchanged. Make the total number of beads the same. LCM of 7 and 8 is 56.
Number of beads that Jeremy gave George
= 21 u - 16 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Number of beads that George had at first
= 16 u
= 16 x 10
= 160
Answer(s): 160
