Luis had
38 the number of buttons that Carl had at first. After Carl gave Luis 99 of his buttons, Luis had
35 the number of buttons that Carl had. How many buttons did Luis have at first?
|
Luis |
Carl |
Total |
Before |
3x8 = 24 u |
8x8 = 64 u |
11x8 = 88 u |
Change |
+ 9 u |
- 9 u |
|
After |
3x11 = 33 u |
5x11 = 55 u |
8x11 = 88 u |
The total number of buttons that Luis and Carl had at first and in the end remains unchanged. Make the total number of buttons the same. LCM of 11 and 8 is 88.
Number of buttons that Carl gave Luis
= 33 u - 24 u
= 9 u
9 u = 99
1 u = 99 ÷ 9 = 11
Number of buttons that Luis had at first
= 24 u
= 24 x 11
= 264
Answer(s): 264