Julian had
38 the number of buttons that Warren had at first. After Warren gave Julian 21 of his buttons, Julian had
37 the number of buttons that Warren had. How many buttons did Julian have at first?
|
Julian |
Warren |
Total |
Before |
3x10 = 30 u |
8x10 = 80 u |
11x10 = 110 u |
Change |
+ 3 u |
- 3 u |
|
After |
3x11 = 33 u |
7x11 = 77 u |
10x11 = 110 u |
The total number of buttons that Julian and Warren had at first and in the end remains unchanged. Make the total number of buttons the same. LCM of 11 and 10 is 110.
Number of buttons that Warren gave Julian
= 33 u - 30 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Number of buttons that Julian had at first
= 30 u
= 30 x 7
= 210
Answer(s): 210