Jenson had
25 the number of coins that Ben had at first. After Ben gave Jenson 120 of his coins, Jenson had
45 the number of coins that Ben had. How many coins did Ben have in the end?
|
Jenson |
Ben |
Total |
Before |
2x9 = 18 u |
5x9 = 45 u |
7x9 = 63 u |
Change |
+ 10 u |
- 10 u |
|
After |
4x7 = 28 u |
5x7 = 35 u |
9x7 = 63 u |
The total number of coins that Jenson and Ben had at first and in the end remains unchanged. Make the total number of coins the same. LCM of 7 and 9 is 63.
Number of coins that Ben gave Jenson
= 28 u - 18 u
= 10 u
10 u = 120
1 u = 120 ÷ 10 = 12
Number of coins that Ben had in the end
= 35 u
= 35 x 12
= 420
Answer(s): 420